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Factorise: x6 – 124x3 – 125 - Mathematics

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प्रश्न

Factorise:

x6 – 124x3 – 125

बेरीज
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उत्तर

To factorise x6 – 124x3 – 125, let’s first treat this expression as a quadratic in terms of x3.

Let y = x3.

The expression becomes:

y2 – 124y – 125

Now, factor the quadratic expression:

y2 – 124y – 125 = (y – 125) (y + 1)

Substitute y = x3 back into the factored expression:

(x3 – 125) (x3 + 1)

Both of these terms are differences and sums of cubes:

x3 – 125 = (x – 5) (x2 + 5x + 25)

x3 + 1 = (x + 1) (x2 – x + 1)

Thus, the fully factorised form of x6 – 124x3 – 125 is (x – 5) (x + 1)(x2 + 5x + 25) (x2 – x + 1)

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पाठ 4: Factorisation - EXERCISE 4D [पृष्ठ ४६]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 4 Factorisation
EXERCISE 4D | Q IV. 3. | पृष्ठ ४६
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