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Factorise: x6 + 26x3 – 27 - Mathematics

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प्रश्न

Factorise:

x6 + 26x3 – 27

बेरीज
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उत्तर

To factorise x6 + 26x3 – 27, notice that we can treat this as a quadratic expression in terms of x3.

Let y = x3.

Then the expression becomes:

y2 + 26y – 27

Now, factor the quadratic expression:

y2 + 26y – 27 = (y + 27) (y – 1)

Substitute y = x3 back into the factored expression:

(x3 + 27) (x3 – 1)

Next, factor each of these terms further.

Both are differences and sums of cubes:

x3 + 27 = (x + 3) (x2 – 3x + 9)

x3 – 1 = (x – 1) (x2 + x + 1)

Thus, the fully factorized form of x6 + 26x3 – 27 is (x + 3) (x – l) (x2 – 3x + 9) (x2 + x + 1)

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पाठ 4: Factorisation - EXERCISE 4D [पृष्ठ ४६]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 4 Factorisation
EXERCISE 4D | Q IV. 2. | पृष्ठ ४६
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