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प्रश्न
Factorise:
x6 + 26x3 – 27
बेरीज
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उत्तर
To factorise x6 + 26x3 – 27, notice that we can treat this as a quadratic expression in terms of x3.
Let y = x3.
Then the expression becomes:
y2 + 26y – 27
Now, factor the quadratic expression:
y2 + 26y – 27 = (y + 27) (y – 1)
Substitute y = x3 back into the factored expression:
(x3 + 27) (x3 – 1)
Next, factor each of these terms further.
Both are differences and sums of cubes:
x3 + 27 = (x + 3) (x2 – 3x + 9)
x3 – 1 = (x – 1) (x2 + x + 1)
Thus, the fully factorized form of x6 + 26x3 – 27 is (x + 3) (x – l) (x2 – 3x + 9) (x2 + x + 1)
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