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Question
Factorise using factor theorem:
x3 + 13x2 + 31х − 45
Sum
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Solution
Let p(x) = x3 + 13x2 + 31х − 45
Factors of constant term – 45 are ±1, ±3, ±5, ±9
Put x = 1;
p(1) = 13 + 13(1)2 + 31(1) − 45
= 1 + 13 + 31 − 45
= 0
x − 1 is a factor of p(x).
x2 + 14x + 45
`x − 1")"overline(x^3 + 13x^2 + 31x - 45)`
− x3 − x2
− +
14x2 + 31x
14x2 − 14x
− +
45x − 45
45x − 45
− +
x
x3 + 13x2 + 31х − 45 = (x − 1) (x2 + 14x + 45)
= (x − 1) (x2 + 9x + 5x + 45)
= (x − 1) [x(x + 9) + 5(x + 9)]
= (x − 1) (x + 5) (x + 9)
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Chapter 6: Factorisation of polynomials - Exercise 6A [Page 105]
