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Question
Factorise the following:
x6 – 63x3 – 64
Sum
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Solution
Given expression: x6 – 63x3 – 64
Step-wise calculation:
1. Let y = x3.
Then the expression becomes y2 – 63y – 64.
2. Factorising the quadratic in y:
We look for two numbers that multiply to (–64) and add to (–63).
These numbers are (–64) and (1).
So, y2 – 63y – 64 = (y – 64)(y + 1).
3. Substitute back y = x3: (x3 – 64)(x3 + 1).
4. Factorise each as a difference and sum of cubes:
x3 – 64 = x3 – 43
x3 – 64 = (x – 4)(x2 + 4x + 16)
x3 + 1 = x3 + 13
x3 + 1 = (x + 1)(x2 – x + 1)
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