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Question
Factorise the following:
(x2 + 2x)2 – 18(x2 + 2x) + 45
Sum
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Solution
Given expression: (x2 + 2x)2 – 18(x2 + 2x) + 45
Step-wise calculation:
1. Let (p = x2 + 2x), substituting gives: p2 – 18p + 45
2. Factorize the quadratic in (p):
Find two numbers whose product is 45 and sum is 18.
Those numbers are 15 and 3.
p2 – 18p + 45 = p2 – 15p – 3p + 45
p2 – 18p + 45 = p(p – 15) – 3(p – 15)
p2 – 18p + 45 = (p – 15)(p – 3)
3. Substitute back (p = x2 + 2x):
(x2 + 2x – 15)(x2 + 2x – 3)
4. Factorise each quadratic:
For (x2 + 2x – 15), factors of –15 adding to 2 are 5 and –3: (x + 5)(x – 3)
For (x2 + 2x – 3), factors of –3 adding to 2 are 3 and –1: (x + 3)(x – 1)
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