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Question
Factorise the following using suitable identity
y2 + 20y + 100
Sum
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Solution
y2 + 20y + 100 = y2 + (2 × (10))y + (10 × 10)
= y2 + (2 × 10 × y) + 102
This is of the form of identity
a2 + 2ab + b2 = (a + b)2
y2 + (2 × 10 × y) + 102 = (y + 10)2
y2 + 20y + 100 = (y + 10)2
y2 + 20y + 100 = (y + 10)(y + 10)
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Chapter 3: Algebra - Exercise 3.1 [Page 62]
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