Advertisements
Advertisements
प्रश्न
Factorise the following using suitable identity
y2 + 20y + 100
बेरीज
Advertisements
उत्तर
y2 + 20y + 100 = y2 + (2 × (10))y + (10 × 10)
= y2 + (2 × 10 × y) + 102
This is of the form of identity
a2 + 2ab + b2 = (a + b)2
y2 + (2 × 10 × y) + 102 = (y + 10)2
y2 + 20y + 100 = (y + 10)2
y2 + 20y + 100 = (y + 10)(y + 10)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
APPEARS IN
संबंधित प्रश्न
Find the following squares by suing the identities.
(6x2 − 5y)2
Use the formula to find the value.
502 × 498
Expand: (2a – 3b)2
Expand: (10 + y)2
Use a formula to multiply of (2t – 5)(2t + 5)
Factors of 9x2 + 6xy are
If a + b = 5 and a2 + b2 = 13, then ab = ?
(a + b)2 = a2 + b2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
9x2 + 30x + 25
If p + q = 12 and pq = 22, then find p2 + q2.
