Advertisements
Advertisements
प्रश्न
Factorise the following using suitable identity
y2 + 20y + 100
Advertisements
उत्तर
y2 + 20y + 100 = y2 + (2 × (10))y + (10 × 10)
= y2 + (2 × 10 × y) + 102
This is of the form of identity
a2 + 2ab + b2 = (a + b)2
y2 + (2 × 10 × y) + 102 = (y + 10)2
y2 + 20y + 100 = (y + 10)2
y2 + 20y + 100 = (y + 10)(y + 10)
APPEARS IN
संबंधित प्रश्न
Use a suitable identity to get the following products.
(x + 3) (x + 3)
Using a2 − b2 = (a + b) (a − b), find (1.02)2 − (0.98)2
Using (x + a) (x + b) = x2 + (a + b) x + ab, find 103 × 104
Use an expansion formula to find the value.
(97)2
Use the formula to multiply the following.
(x + y) (x − y)
Evaluate the following, using suitable identity
512
Simplify: (a + b)2 + (a – b)2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abx + b2
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 12x + 9
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x4 + 12x3 + 9x2
