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Question
Factorise the following:
p(a2 + a – b) + q(b – a – a2)
Sum
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Solution
Given expression: p(a2 + a – b) + q(b – a – a2)
Step-wise calculation:
1. Rearrange the terms inside the parentheses for the second part:
q(b – a – a2) = q(–a2 – a + b)
2. So the expression becomes:
p(a2 + a – b) + q(–a2 – a + b)
3. Group terms by (a2), (a) and (b):
= pa2 + pa – pb – qa2 – qa + qb
4. Combine like terms:
= (pa2 – qa2) + (pa – qa) + (–pb + qb)
= (p – q)a2 + (p – q)a + (q – p)b
5. Factor out (p – q) where possible:
= (p – q)(a2 + a) + (q – p)b
6. Note that (q – p)b = –(p – q)b, so:
= (p – q)(a2 + a) – (p – q)b
7. Factor out (p – q) completely:
= (p – q)(a2 + a – b)
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