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Question
Factorise the following:
`27p^3-1/216-9/2p^2+1/4p`
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Solution
`27p^3 - 1/216 - 9/2p^2 + 1/4p`
= `(3p)^3 - (1/6)^3 - 3(3p)(1/6)(3p - 1/6)`
= `(3p-1/6)^3` ...[Using a3 − b3 − 3ab(a − b) = (a − b)3]
= `(3p-1/6)(3p-1/6)(3p-1/6)`
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