Advertisements
Advertisements
Question
Factorise by the grouping method: 16 (a + b)2 - 4a - 4b
Sum
Advertisements
Solution
16 (a + b)2 - 4a - 4b
= 16 (a + b)2 - 4 (a + b)
= (a + b) [16 (a + b) - 4]
= 4 (a + b) [4 (a + b) - 1]
= 4 (a + b) (4a + 4b - 1)
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise by the grouping method : a4 - 2a3 - 4a + 8
Factorise : - x2y - x + 3xy + 3
Factorise : (a2 − b2) c + (b2 − c2)a
Factorise : ab(c2 + d2) - a2cd - b2cd
factorise: 3a2 - 5a + 2
factorise: 2a2 - 17ab + 26b2
factorise: 4c2 + 3c - 10
factorise: a2 - 23a + 42
Factorise the following by grouping the terms:
8(2a + b)2 - 8a -4b
Factorise the following by grouping the terms:
x(x - 4)- x + 4
