Advertisements
Advertisements
Question
Factorise by the grouping method: 16 (a + b)2 - 4a - 4b
Sum
Advertisements
Solution
16 (a + b)2 - 4a - 4b
= 16 (a + b)2 - 4 (a + b)
= (a + b) [16 (a + b) - 4]
= 4 (a + b) [4 (a + b) - 1]
= 4 (a + b) (4a + 4b - 1)
shaalaa.com
Factorisation by Grouping
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise by the grouping method :
`a^2 + 1/a^2 - 2 - 3a + 3/a`
Factorise using the grouping method :
a2 + 4b2 - 3a + 6b - 4ab
Factorise : xy - ay - ax + a2 + bx - ab
Factorise : 2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c
factorise: x2 + 4x + 3
factorise: 14x2 + x - 3
factorise: (2a + b)2 + 5(2a + b) + 6
factorise: 5x2 - 4xy - 12y2
Factorise the following by grouping the terms:
x + y + m(x + y)
Factorise the following by grouping the terms:
`(1)/(25x^2) + 16x^2 + (8)/(5) - 12x - (3)/(5x)`
