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Question
Factorise by substituting terms:
12(a + b)2 – 5(a + b) – 3
Sum
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Solution
12(a + b)2 – 5(a + b) – 3
Let a + b = y
= 12y2 – 5y – 3
= 12y2 – 9y + 4y – 3
= 3y(4y – 3) + 1(4y – 3)
= (4y – 3) (3y + 1)
= [4 (a + b) – 3] [3 (a + b) + 1]
= (4a + 4b – 3) (3a + 3b + 1)
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