Given expression: 8a4 + 27a ⇒ a2a3 + 33 We know that, a3 + b3 = (a + b) (a2 – ab + b2) Hence, ⇒ a(2a + 3) (4a2 – 6a + 9)

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Factorise: 8a4 + 27a - Mathematics

Factorise:

8a⁴ + 27a

Sum

Given expression: 8a⁴ + 27a

⇒ a2a³ + 3³

We know that,

a³ + b³ = (a + b) (a² – ab + b²)

Hence,

⇒ a(2a + 3) (4a² – 6a + 9)

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Chapter 4: Factorisation - EXERCISE 4D [Page 46]

Chapter 4 Factorisation
EXERCISE 4D | Q I. 10. | Page 46

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