Advertisements
Advertisements
Question
Factorise : 64 - a3b3
Sum
Advertisements
Solution
64 - a3b3
= (4)3 - (ab)3
= ( 4 - ab )[(4)2 + 4 x ab + (ab)2 ] [ ∵ a3 - b3 = ( a - b )( a2 + ab + b2 )]
= ( 4 - ab )( 16 + 4ab + a2b2 )
shaalaa.com
Method of Factorisation : the Sum Or Difference of Two Cubes
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : a6 + 27b3
Factorise : a3 - `27/a^3`
Factorise : a3 + 0.064
Factorise : a3 + 0.064
Factorise: (x - y)3 - 8x3
Factorise:
a4 - 343a
Factorise : 2x3 + 54y3 - 4x - 12y
Factorise : 8a3 - b3 - 4ax + 2bx
Factorise : a - b - a3 + b3
Evaluate :
`[ 5.67 xx 5.67 xx 5.67 + 4.33 xx 4.33 xx 4.33 ]/[5.67 xx 5.67 - 5.67 xx 4.33 + 4.33 xx 4.33]`
