Advertisements
Advertisements
Question
Factorise : `4x^2 + 1/(4x)^2 + 1`
Sum
Advertisements
Solution
`4x^2 + 1/(4x)^2 + 1`
= `4x^2 + 1/(4x)^2 + 2 - 1`
= `4x^2 + 1/(4x)^2 + 2 xx 2x xx 1/(2x) - 1`
= `( 2x + 1/(2x) + 1)^2 - (1)^2`
= `( 2x + 1/(2x) + 1 )( 2x + 1/(2x) - 1 )`
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : 50a3 - 2a
Factorise : a4 - 1
Factorise : a3 + 2a2 - a - 2
Factorise : a (a - 1) - b (b - 1)
Factorise : 4a2 - 12a + 9 - 49b2
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following:
9(a - b)2 - (a + b)2
Factorise the following:
b2 - 2bc + c2 - a2
Factorise the following:
y4 + y2 + 1
