Advertisements
Advertisements
Question
Factorise : `4x^2 + 1/(4x)^2 + 1`
Sum
Advertisements
Solution
`4x^2 + 1/(4x)^2 + 1`
= `4x^2 + 1/(4x)^2 + 2 - 1`
= `4x^2 + 1/(4x)^2 + 2 xx 2x xx 1/(2x) - 1`
= `( 2x + 1/(2x) + 1)^2 - (1)^2`
= `( 2x + 1/(2x) + 1 )( 2x + 1/(2x) - 1 )`
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : 25(2a - b)2 - 81b2
Factorise : a3 + 2a2 - a - 2
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise : (a + b) 2 - a2 + b2
Factorise the following by the difference of two squares:
64x2 - 121y2
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following by the difference of two squares:
625 - b2
Factorise the following by the difference of two squares:
x2 + y2 - z2 - 2xy
Factorise the following:
(x2 + y2 – z2)2 – 4x2y2
Factorise the following:
4xy - x2 - 4y2 + z2
