Advertisements
Advertisements
Question
Factorise:
(2a + b)2 - 6a - 3b - 4
Sum
Advertisements
Solution
(2a + b)2 - 6a - 3b - 4
= (2a + b)2 - 3(2a + b) - 4
Assume that, 2a + b = x
Therefore,
(2a + b)2 - 6a - 3b - 4
= x2 - 3x - 4
= x2 - 4x + x - 4
= 1(x - 4) + x(x - 4)
= (x + 1)(x - 4)
= (2a + b + 1)(2a + b - 4)
[resubstitute the value of x]
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise.
x2 − 10x + 9
Factorise.
p2 − 7p − 44
Factorise : x2 - 3ax - 88a2
Factorise : 1 - 2a - 2b - 3 (a + b)2
Factorise: 5 - (3a2 - 2a) (6 - 3a2 + 2a)
Find trinomial (quadratic expression), given below, find whether it is factorisable or not. Factorise, if possible.
x(2x - 1) - 1
Factorise : 7√2x2 - 10x - 4√2
Factorise the following:
`6sqrt(3)x^2 - 19x + 5sqrt(3)`
Factorise the following:
(t2 - t)(4t2 - 4t - 5) - 6
Factorise the following:
6 - 5x + 5y + (x - y)2
