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Question
factorise : 25(2x - y)2 - 16(x - 2y)2
Sum
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Solution
25(2x - y)2 - 16(x - 2y)2
= (5 (2x - y))2 - (4 (x - 2y))2
= [5(2x - y) - 4 (x - 2y)][5(2x - y) + 4(x - 2y)]
= [10x - 5y - 4x + 8y][10x - 5y + 4x - 8y]
....[a2 - b2 = (a - b)(a + b)]
= (6x + 3y)(14x - 13y)
= 3(2x + y)(14x - 13y)
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Factorisation by Difference of Two Squares
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