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Question
Express the following in the exponential form:
`"log"_sqrt(6) (6sqrt(6))` = 3
Sum
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Solution
`"log"_sqrt(6) (6sqrt(6))` = 3
⇒ `6sqrt(6) = (sqrt(6))^3`.
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Interchanging Logarithmic and Exponential Forms - Logarithmic to Exponential
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