Advertisements
Advertisements
Question
Explain the variation in `"E"_ ("M"^(3+)//"M"^(2+))^0` 3d series.
Advertisements
Solution
Transition metals in their high oxidation states tend to be oxidising. The standard reduction potential for the M3+/M2+ half cell gives the relative stability between M3+ and M2+.
| Reaction | Standard reduction potential (V) |
| \[\ce{Ti^3+ + e^- -> Ti^2+}\] | −0.37 |
| \[\ce{Y^3+ + e^- -> V^2+}\] | −0.26 |
| \[\ce{Cr^3+ + e^- -> Cr^2+}\] | −0.41 |
| \[\ce{Mn^3+ + e^- -> Mn^2+}\] | +1.51 |
| \[\ce{Fe^3+ + e^- -> Fe^2+}\] | +0.77 |
| \[\ce{Co^3+ + e^- -> Co^2+}\] | +1.81 |
The negative values for titanium, vanadium and chromium indicate that the higher oxidation state is preferred.
The high reduction potential of M3+/M2+ indicates Mn2+ is more stable than Mn3+.
APPEARS IN
RELATED QUESTIONS
Which one of the following ions has the same number of unpaired electrons as present in V3+?
The correct order of increasing oxidizing power in the series
Complete the following.
\[\ce{MnO^2-_4 + H^+ ->?}\]
What are interstitial compounds?
Calculate the number of unpaired electrons in Ti3+, Mn2+ and calculate the spin only magnetic moment.
Explain briefly how +2 states become more and more stable in the first half of the first-row transition elements with increasing atomic numbers.
The `"E"_("M"^(2+)//"M")^0` value for copper is positive. Suggest a possible reason for this.
Describe the variable oxidation state of 3d series elements.
Which metal in the 3d series exhibits +1 oxidation state most frequently and why?
Why first ionization enthalpy of chromium is lower than that of zinc?
