Advertisements
Advertisements
Question
Explain the following:
The reducing power of element increases down in the group while decreases in a period.
Advertisements
Solution
The reducing property depends on the ionisation potential and electron affinity of the elements. In a period, from left to right in a horizontal row of the periodic table, the atomic size decreases and the nuclear charge increases, so the electron affinity and ionisation energy both increase. Hence, the tendency to lose electrons decreases across the period from left to right and thus the reducing property also decreases across the period from left to right.
The electron affinity and ionisation potential decreases along the group from top to bottom. Hence, the tendency to lose electrons increases, and thus, the reducing property also increases along the group from top to bottom.
APPEARS IN
RELATED QUESTIONS
Draw an electron dot diagram to show the formation of each of the following compounds:
Magnesium Chloride
[H = 1, C = 6, Mg = 12, Cl = 17]
Arrange the elements of group 17 and group 1 according to the given conditions.
Increasing electron affinity
Which has higher E.A. fluorine or Neon?
An element in period 3, whose electron affinity is zero:
F, B, N, O (In the increasing order of electron affinity)
Why is the electron affinity of fluorine less than chlorine?
Down the group, electron affinity ______.
Arrange the following as per instruction given in the bracket.
Cl, F, Br, I (increasing electron affinity)
Arrange the following as per instruction given in the bracket.
Cl, F, Br, I (increasing electron affinity)
In Period 3 of the Periodic Table, element B is placed to the left of element A. On the basis of this information, choose the correct word from the option to complete the following statement:
The element A would probably have ______ electron affinity than B.
