Expand : ( X + 8 )( X - 10 )

Expand : ( x + 8 )( x - 10 )

Sum

( x + 8 )( x - 10 ) = x² + ( 8 - 10 )x + 8 x (-10)
= x² - 2x - 80

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Chapter 4: Expansions (Including Substitution) - Exercise 4 (C) [Page 62]

Chapter 4 Expansions (Including Substitution)
Exercise 4 (C) | Q 1.2 | Page 62

If a + b + c = p and ab + bc + ca = q ; find a² + b² + c².

In the expansion of (2x² - 8) (x - 4)²; find the value of constant term.

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(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

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If 3a + 5b + 4c = 0, show that : 27a³ + 125b³ + 64c³ = 180 abc

If x = `1/( x - 5 ) "and x ≠ 5. Find" : x^2 - 1/x^2`