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Question
Expand the following:
(5ab − 4cd)2
Sum
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Solution
(5ab − 4cd)2
Using the identity:
(a − b)2 = a2 − 2ab + b2
Here, let a = 5ab, b = 4cd
Thus,
(5ab − 4cd)2 = (5ab)2 − 2(5ab)(4cd) + (4cd)2
= 25a2b2 − 2(20abcd) + 16c2d2
∴ (5ab − 4cd)2 = 25a2b2 − 40abcd + 16c2d2
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