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Question
Expand the following:
(2ab + 3cd)2
Sum
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Solution
(2ab + 3cd)2
Here, a = 2ab, b = 3cd
Thus,
(2ab + 3cd)2 = (2ab)2 + 2(2ab)(3cd) + (3cd)2 ...[Using (a ± b)2 = a2 ± 2ab + b2]
4a2b2 + 2(6abcd) + 9c2d2
∴ 4a2b2 + 12abcd + 9c2d2
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Chapter 3: Expansions - EXERCISE A [Page 32]
