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Question
Expand:
(4a − 5b − 6)2
Sum
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Solution
(4a − 5b − 6)2
Here, let a = 4a, b = −5b, c = −6
Using the identity,
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Thus,
= (4a − 5b − 6)2 = (4a)2 + (−5b)2 + (−6)2 + 2(4a)(−5b) + 2(−5b)(−6) + 2(−6)(4a)
= 16a2 + 25b2 + 36 + 2(−20ab) + 2(−30b) + 2(24ac)
∴ (2a − 3b + 5c)2 = 16a2 + 25b2 + 36 − 40ab + 60b − 48a
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Chapter 3: Expansions - EXERCISE C [Page 38]
