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Question
Evaluate `|(x, x + 1),(x - 1, x)|`
Options
1
2
3
4
MCQ
Solution
1
Explanation:
We have, `|(x, x + 1),(x - 1, x)|`
= `(x)x - (x + 1)(x - 1)`
= `x^2 - (x^2 - 1)`
= `(x^2 - x^2 + 1)`
= 1
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