Question

Evaluate `|(x, x + 1),(x - 1, x)|`

विकल्प

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Answer 1

1

Explanation:

We have, `|(x, x + 1),(x - 1, x)|`

= `(x)x - (x + 1)(x - 1)`

= `x^2 - (x^2 - 1)`

= `(x^2 - x^2 + 1)`

= 1