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Evaluate ∫x2e4x dx

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Question

Evaluate `int x^2"e"^(4x)  "d"x`

Sum
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Solution

Let I = `int x^2*"e"^(4x)  "d"x`

= `x^2 int "e"^(4x) "d"x - int ["d"/("d"x)(x^2) int"e"^(4x)"d"x]"d"x`

= `x^2* ("e"^(4x))/4 - int 2x* ("e"^(4x))/4  "d"x`

= `(x^2*"e"^(4x))/4 - 1/2 intx*"e"^(4x)"d"x`

= `(x^2"e"^(4x))/4 - 1/2[x"f""e"^(4x)"d"x - int("d"/("d"x)(x) int"e"^(4x)"d"x)"d"x]`

= `(x^2"e"^(4x))/4 - 1/2[x* ("e"^(4x))/4 - int 1* ("e"^(4x))/4 "d"x]`

= `(x^2"e"^(4x))/4 - 1/2[(x*"e"^(4x))/4 - 1/4 int"e"^(4x)"d"x]`

= `(x^2"e"^(4x))/4 - 1/2[(x"e"^(4x))/4 - 1/4*("e"^(4x))/4] + "c"`

= `(x^2"e"^(4x))/4 - (x"e"^(4x))/8 + ("e"^(4x))/32 + "c"`

∴ I = `("e"^(4x))/4[x^2 - x/2 + 1/8] + "c"`

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Chapter 1.5: Integration - Q.4

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