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Evaluate the following without using a table: 2⁢tan⁡32°cot⁡58° +sec⁡46°cosec44° - Mathematics

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Question

Evaluate the following without using a table:

`2 (tan 32°)/(cot 58°) + (sec 46°)/("cosec" 44°)`

Sum
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Solution

Given:

`2 (tan 32°)/(cot 58°) + (sec 46°)/("cosec" 44°)`

Step 1:

cot(90° − θ) = tan θ and cosec(90° − θ) = sec θ

Since 58° = 90° − 32°

cot 58° = tan 32°

`(tan 32°)/(cot 58°)` = 1 

so 2 × 1 = 2     ...[(i)]

Step 2:

44° = 90° − 46°, cosec 44° = sec 46°

`(sec 46°)/("cosec" 44°)` = 1     ...[(ii)]

= 2 + 1    ...[Adding (i) & (ii)]

= 3

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Chapter 19: Trigonometry - MISCELLANEOUS EXERCISE [Page 239]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 19 Trigonometry
MISCELLANEOUS EXERCISE | Q IV. 1. | Page 239
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