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Evaluate the following: (sec 48^circ)/(cosec 42^circ) - Mathematics

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Question

Evaluate the following:

`(sec 48^circ)/("cosec"  42^circ)`

Evaluate
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Solution

Given: `(sec 48^circ)/("cosec"  42^circ)`

48° = 90° – 42° 

So, sec 48° = sec (90° – 42°) 

= `1/cos(90^circ - 42^circ)` 

= `1/(sin 42^circ)` 

= cosec 42° 

Therefore, `(sec 48^circ)/("cosec"  42^circ)`

= `("cosec"  42^circ)/("cosec"  42^circ)`

= 1

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Chapter 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18C [Page 380]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 18 Trigonometric Ratios of Some Standard Angles and Complementary Angles
Exercise 18C | Q 1. (ii) | Page 380
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