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Question
Evaluate the determinant.
`|(2,-1,-2),(0,2,-1),(3,-5,0)|`
Evaluate
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Solution
`|(2,-1,-2),(0,2,-1),(3,-5,0)|`
= `2|(2,-1),(-5,0)| + 1|(0,-1),(3,0)| - 2|(0,2),(3,-5)|`
= 2[2 × 0 − (−1) × (−5)] + 1[0 × 0 − (−1) × 3] − 2[0 × (−5) − 2 × 3]
= 2(0 − 5) + 1(0 + 3) − 2(0 − 6)
= −10 + 3 + 12
= 5
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