English

Evaluate the definite integral: ∫π2πex(1-sinx1-cosx)dx - Mathematics

Advertisements
Advertisements

Question

Evaluate the definite integral:

`int_(pi/2)^pi e^x ((1-sinx)/(1-cos x)) dx`

Sum
Advertisements

Solution

Let I = `int e^x ((1 - sin x)/(1 + cos x))`dx

`= int e^x [(1 - 2 sin  x/2 cos  x/2)/(2 sin^2  x/2)]`dx

`= int e^x (1/2 cosec^2 * x/2 - cot  x/2)`dx

`= - int cot  x/2 e^x dx + 1/2 int e^x cosec^2  x/2  dx`

`= - [cot  x/2 * e^x - int - 1/2 cosec^2 x/2 e^x dx] + 1/2 int cosec x/2 * e^x  dx`

`= - e^x cot  x/2 - 1/2 int cosec^2  x/2 * e^x dx + 1/2 int cosec^2  x/2 * e^x  dx`

`= - e^x  cot  x/2`

`therefore int_(pi/2)^pi e^x  ((1 - sin x)/(1 + cos x))`dx

`= - [e^x cot  x/2]_(pi/2)^pi`

`= - [pi cot  pi/2 - e^(pi/2) cot  pi/4]`

`= - 0 + e^(pi/2) * 1`

`= e^(pi/2)`

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise 7.12 [Page 353]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.12 | Q 25 | Page 353

RELATED QUESTIONS

Evaluate the following definite integrals as limit of sums.

`int_0^5 (x+1) dx`


Evaluate the definite integral:

`int_0^(pi/4) (sinx cos x)/(cos^4 x + sin^4 x)`dx


Evaluate the definite integral:

`int_0^1 dx/(sqrt(1+x) - sqrtx)`


Evaluate the definite integral:

`int_0^(pi/2) sin 2x tan^(-1) (sinx) dx`


Prove the following:

`int_0^(pi/2) sin^3 xdx = 2/3`


`int dx/(e^x + e^(-x))` is equal to ______.


` ∫  log x / x  dx `
 
 
 

\[\int\frac{\sin^3 x}{\sqrt{\cos x}} dx\]

\[\int\frac{1}{x} \left( \log x \right)^2 dx\]


\[\int\frac{\sin x}{\left( 1 + \cos x \right)^2} dx\]

 


\[\int x^3 \sin \left( x^4 + 1 \right) dx\]

\[\int\frac{1}{x^2} \cos^2 \left( \frac{1}{x} \right) dx\]

\[\int \sec^4    \text{ x   tan x dx} \]

\[\int\frac{1}{x\sqrt{x^4 - 1}} dx\]

\[\int\limits_0^\pi \frac{\sin x}{\sin x + \cos x} dx\]

Evaluate the following integral:

\[\int\limits_{- 1}^1 \left| 2x + 1 \right| dx\]

\[\int\limits_{- \pi/2}^{\pi/2} \sin^4 x\ dx\]

Evaluate the following integrals as limit of sums:

\[\int_1^3 \left( 3 x^2 + 1 \right)dx\]

\[\int\frac{\sqrt{\tan x}}{\sin x \cos x} dx\]


Solve: (x2 – yx2) dy + (y2 + xy2) dx = 0 


Evaluate `int_(-1)^2 (7x - 5)"d"x` as a limit of sums


If f and g are continuous functions in [0, 1] satisfying f(x) = f(a – x) and g(x) + g(a – x) = a, then `int_0^"a" "f"(x) * "g"(x)"d"x` is equal to ______.


Evaluate the following as limit of sum:

`int _0^2 (x^2 + 3) "d"x`


Evaluate the following:

`int_0^1 (x"d"x)/sqrt(1 + x^2)`


Evaluate the following:

`int_0^(1/2) ("d"x)/((1 + x^2)sqrt(1 - x^2))`  (Hint: Let x = sin θ)


The value of `int_(-pi)^pi sin^3x cos^2x  "d"x` is ______.


The value of `lim_(x -> 0) [(d/(dx) int_0^(x^2) sec^2 xdx),(d/(dx) (x sin x))]` is equal to


If f" = C, C ≠ 0, where C is a constant, then the value of `lim_(x -> 0) (f(x) - 2f (2x) + 3f (3x))/x^2` is


`lim_(x -> 0) (xroot(3)(z^2 - (z - x)^2))/(root(3)(8xz - 4x^2) + root(3)(8xz))^4` is equal to


The value of  `lim_(n→∞)1/n sum_(r = 0)^(2n-1) n^2/(n^2 + 4r^2)` is ______.


`lim_(n→∞){(1 + 1/n^2)^(2/n^2)(1 + 2^2/n^2)^(4/n^2)(1 + 3^2/n^2)^(6/n^2) ...(1 + n^2/n^2)^((2n)/n^2)}` is equal to ______.


`lim_(n rightarrow ∞)1/2^n [1/sqrt(1 - 1/2^n) + 1/sqrt(1 - 2/2^n) + 1/sqrt(1 - 3/2^n) + ...... + 1/sqrt(1 - (2^n - 1)/2^n)]` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×