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Evaluate: sin ⁡[π/3 – sin^–1 ⁡(–1/2)]. - Mathematics

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Question

Evaluate: `sin [π/3 - sin^-1 (-1/2)]`.

Evaluate
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Solution

`sin [π/3 - (- π/6)]`

= `sin  π/2`

= 1

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2019-2020 (March) Delhi Set 2
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