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Evaluate \[\int_0^{\frac\pi4}\sin^3 2t\cos 2t\,dt.\]

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Question

Evaluate \[\int_0^{\frac\pi4}\sin^3 2t\cos 2t\,dt.\]

Options

  • \[\frac18\]

  • \[\frac14\]

  • \[0\]

  • \[\frac\pi4\]

MCQ
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Solution

Use \(F(t)=\frac18\sin^4 2t\) and compute \(F\left(\frac\pi4\right)-F(0)\).
Since \(\sin\frac\pi2=1\) and \(\sin0=0\), the value is \(\frac18\).

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