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Question
Evaluate \[\int_{0}^{1}x\,dx\].
Options
\[0\]
\[\frac{1}{2}\]
\[1\]
\[2\]
MCQ
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Solution
Using \[\frac{x^2}{2}\], the value is \[\left[\frac{x^2}{2}\right]_{0}^{1}\]. Thus, \[\frac{1^2}{2}-\frac{0^2}{2}=\frac{1}{2}\].
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