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Evaluate \[\int \frac{dx}{\sqrt{x^2-a^2}}\].

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Question

Evaluate \[\int \frac{dx}{\sqrt{x^2-a^2}}\].

Options

  • \[\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)+C\]

  • \[\log\left|x+\sqrt{x^2+a^2}\right|+C\]

  • \[\log\left|x+\sqrt{x^2-a^2}\right|+C\]

  • \[\sin^{-1}\left(\frac{x}{a}\right)+C\]

MCQ
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Solution

The radical \[\sqrt{x^2-a^2}\] corresponds to a logarithmic standard integral. The expression under the logarithm retains the form \[x+\sqrt{x^2-a^2}\].

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