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Question
Evaluate cot(tan−1(2x) + cot−1(2x))
Sum
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Solution
cot(tan−1(2x) + cot−1(2x)) = `cot (pi/2)`
= 0 .......`[∵ tan^-1x + cot^-1 x = pi/2]`
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Evaluate cot(tan−1(2x) + cot−1(2x))
cot(tan−1(2x) + cot−1(2x)) = `cot (pi/2)`
= 0 .......`[∵ tan^-1x + cot^-1 x = pi/2]`