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Evaluate: 70 ×(25)−32 −5−3 - Mathematics

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Question

Evaluate:

`7^0 xx (25)^(-3/2) - 5^(-3)`

Sum
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Solution

`7^0 xx (25)^(-3/2) - 5^(-3)`

= `7^0 xx ( 5 xx 5 )^( -3/2 ) - 5^( -3 )`

= `7^0 xx (5^2)^(-3/2) - 1/5^3`

= `7^0 xx [(5)^[2 xx (-3/2)]] - 1/5^3`

= `7^0 xx 5^(-3) - 1/5^3`

= `1 xx 5^(-3)- 1/5^3`

= `1/5^3 - 1/5^3`

= 0

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Laws of Exponents
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Chapter 7: Indices (Exponents) - Exercise 7 (A) [Page 98]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (A) | Q 1.4 | Page 98
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