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Question
Evaluate:
`int_(pi/6)^(pi/3) cos x dx`
Evaluate
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Solution
`int_(pi/6)^(pi/3) cos x dx`
= `[sin x]_(pi/6)^(pi/3)`
= `sin pi/3 - sin pi/6`
= `(sqrt3)/2 - 1/2`
= `(sqrt3 - 1)/2`
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