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Evaluate: 4^๐‘›+4 โˆ’ 5 ร— 4^๐‘›+2/4^๐‘›+1 ร— 11 - Mathematics

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Question

Evaluate:

`(4^(n + 4) - 5 xx 4^(n + 2))/(4^(n + 1) xx 11)`

Evaluate
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Solution

Given expression is `(4^(n + 4) - 5 xx 4^(n + 2))/(4^(n + 1) xx 11)`

Using the laws of exponents that is `a^(n + m) = a^n xx a^m` we get,

= `(4^n xx 4^4 - 5 xx 4^n xx 4^2)/(4^n xx 4^1 xx 11)`

Now, taking out the common term and simplifying the expression by cancelling out the same term we get,

= `(4^n(4^4 - 5 xx 4^2))/(4^n xx 4^1 xx 11)`

= `(4^4 - 5 xx 4^2)/(4 xx 11)`

= `(4(4^3 - 5 xx 4))/(4 xx 11)`

= `(64 - 20)/11`

= `44/11`

= 4

Therefore, the value of `(4^(n + 4) - 5 xx 4^(n + 2))/(4^(n + 1) xx 11) = 4`

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Chapter 6: Indices - EXERCISE 6 [Page 67]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 10. (v) | Page 67
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