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рдкреНрд░рд╢реНрди
Evaluate:
`(4^(n + 4) - 5 xx 4^(n + 2))/(4^(n + 1) xx 11)`
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Given expression is `(4^(n + 4) - 5 xx 4^(n + 2))/(4^(n + 1) xx 11)`
Using the laws of exponents that is `a^(n + m) = a^n xx a^m` we get,
= `(4^n xx 4^4 - 5 xx 4^n xx 4^2)/(4^n xx 4^1 xx 11)`
Now, taking out the common term and simplifying the expression by cancelling out the same term we get,
= `(4^n(4^4 - 5 xx 4^2))/(4^n xx 4^1 xx 11)`
= `(4^4 - 5 xx 4^2)/(4 xx 11)`
= `(4(4^3 - 5 xx 4))/(4 xx 11)`
= `(64 - 20)/11`
= `44/11`
= 4
Therefore, the value of `(4^(n + 4) - 5 xx 4^(n + 2))/(4^(n + 1) xx 11) = 4`
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