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Evaluate: 7^ЁЭСЫ+2 тИТ 9 ├Ч 7^ЁЭСЫ/7^ЁЭСЫ+1 ├Ч 5 - Mathematics

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Evaluate:

`(7^(n + 2) - 9 xx 7^n)/(7^(n + 1) xx 5)`

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Given expression is `(7^(n + 2) - 9 xx 7^n)/(7^(n + 1) xx 5)`

Using the laws of exponents that is `a^(n + m) = a^n xx a^m` we get,

= `(7^n xx 7^2 - 9 xx 7^n)/(7^n xx 7^1 xx 5)`

Now, taking out the common term and simplifying the expression by cancelling out the same term we get,

= `(7^n7^2 - 9)/(7^n xx 7^1 xx 5)`

= `(49 - 9)/35`

= `40/35`

= `8/7`

Therefore, the value of `(7^(n + 2) - 9 xx 7^n)/(7^(n + 1) xx 5)` is `8/7`.

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рдкрд╛рда 6: Indices - EXERCISE 6 [рдкреГрд╖реНрда ремрен]

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рдмреА рдирд┐рд░реНрдорд▓рд╛ рд╢рд╛рд╕реНрддреНрд░реА Mathematics [English] Class 9 ICSE
рдкрд╛рда 6 Indices
EXERCISE 6 | Q 10. (iv) | рдкреГрд╖реНрда ремрен
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