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рдкреНрд░рд╢реНрди
Evaluate:
`(7^(n + 2) - 9 xx 7^n)/(7^(n + 1) xx 5)`
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Given expression is `(7^(n + 2) - 9 xx 7^n)/(7^(n + 1) xx 5)`
Using the laws of exponents that is `a^(n + m) = a^n xx a^m` we get,
= `(7^n xx 7^2 - 9 xx 7^n)/(7^n xx 7^1 xx 5)`
Now, taking out the common term and simplifying the expression by cancelling out the same term we get,
= `(7^n7^2 - 9)/(7^n xx 7^1 xx 5)`
= `(49 - 9)/35`
= `40/35`
= `8/7`
Therefore, the value of `(7^(n + 2) - 9 xx 7^n)/(7^(n + 1) xx 5)` is `8/7`.
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