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Solve for x: (625)^ЁЭСетИТ1 = (0.008)^3тИТЁЭСе - Mathematics

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Solve for x:

`(625)^(x - 1) = (0.008)^(3 - x)`

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Given expression is `(625)^(x - 1) = (0.008)^(3 - x)`.

We have to find the value of x in given expression.

Thus, 

`(625)^(x - 1) = (0.008)^(3 - x)`

`(5^4)^(x - 1) = (8/1000)^(3 - x)`

`(5^4)^(x - 1) = (2^3/10^3)^(3 - x)`

`(5)^(4x - 4) = (2/10)^(3(3 - x))`  ...`[a^n/b^n = (a/b)^n]`

`(5)^(4x - 4) = (1/5)^(9 - 3x)`

`(5)^(4x - 4) = (5^-1)^(9 - 3x)`

`(5)^(4x - 4) = (5)^(-1(9 - 3x))`

`(5)^(4x - 4) = (5)^(3x - 9)`

Equating the powers with same bases.

4x – 4 = 3x – 9

4x – 3x = 4 – 9

x = –5

Hence, the value of x in given expression is –5.

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рдкрд╛рда 6: Indices - EXERCISE 6 [рдкреГрд╖реНрда ремрен]

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рдмреА рдирд┐рд░реНрдорд▓рд╛ рд╢рд╛рд╕реНрддреНрд░реА Mathematics [English] Class 9 ICSE
рдкрд╛рда 6 Indices
EXERCISE 6 | Q 11. (i) | рдкреГрд╖реНрда ремрен
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