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рдкреНрд░рд╢реНрди
Solve for x:
`(625)^(x - 1) = (0.008)^(3 - x)`
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Given expression is `(625)^(x - 1) = (0.008)^(3 - x)`.
We have to find the value of x in given expression.
Thus,
`(625)^(x - 1) = (0.008)^(3 - x)`
`(5^4)^(x - 1) = (8/1000)^(3 - x)`
`(5^4)^(x - 1) = (2^3/10^3)^(3 - x)`
`(5)^(4x - 4) = (2/10)^(3(3 - x))` ...`[a^n/b^n = (a/b)^n]`
`(5)^(4x - 4) = (1/5)^(9 - 3x)`
`(5)^(4x - 4) = (5^-1)^(9 - 3x)`
`(5)^(4x - 4) = (5)^(-1(9 - 3x))`
`(5)^(4x - 4) = (5)^(3x - 9)`
Equating the powers with same bases.
4x – 4 = 3x – 9
4x – 3x = 4 – 9
x = –5
Hence, the value of x in given expression is –5.
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