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Evaluate: 2^๐‘›+2 + 2^๐‘›/2^๐‘›+2 โˆ’ 2^๐‘›+1 - Mathematics

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Question

Evaluate:

`(2^(n + 2) + 2^n)/(2^(n + 2) - 2^(n + 1))`

Evaluate
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Solution

Given expression is `(2^(n + 2) + 2^n)/(2^(n + 2) - 2^(n + 1))`,

Using the laws of exponents that is `a^(n + m) = a^n xx a^m` we get,

= `(2^n xx 2^2 + 2^n)/(2^n xx 2^2 - 2^n xx 2^1)`

Now, taking out the common term and simplifying the expression by cancelling out the same term we get,

= `(2^n xx 2^2 + 1)/(2^n xx (2^2 - 2))`

= `(2^2 + 1)/(2^2 - 2)`

= `(4 + 1)/(4 - 2)`

= `5/2`

Therefore, the value of `(2^(n + 2) + 2^n)/(2^(n + 2) - 2^(n + 1)) = 5/2`.

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Chapter 6: Indices - EXERCISE 6 [Page 67]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 6 Indices
EXERCISE 6 | Q 10. (iii) | Page 67
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