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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Evaluate: (2−1 × 3−1) ÷ 6−2 - Mathematics

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Question

Evaluate: (2−1 × 3−1) ÷ 6−2 

Sum
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Solution

(2−1 × 3−1) ÷ 6−2 = (2 × 3)1 ÷ 62 

= (61) ÷ 62

= `6^((-1)-(-2))`

= 61

= 6

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Chapter 1: Numbers - Exercise 1.6 [Page 45]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 1 Numbers
Exercise 1.6 | Q 3. (v) | Page 45
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