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Evaluate: 1012 – 1002 - Mathematics

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Question

Evaluate: 1012 – 1002

Sum
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Solution

1012 – 1002
Using property, for any natural number n,
(n + 1)2  – n2 = (n + 1) + n
⇒ (100 + 1)2  – 1002 = (100 + 1) + 100
⇒ 1012  – 1002 = 101 + 100
⇒ 1012  – 1002 = 201

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Chapter 3: Squares and Square Root - Exercise 3 (C) [Page 45]

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Selina Concise Mathematics [English] Class 8 ICSE
Chapter 3 Squares and Square Root
Exercise 3 (C) | Q 12.3 | Page 45

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