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Question
Ethene reacts with 1% cold alkaline KMnO4 to give
Options
Oxalic acid
Ethyl alcohol
Acetaldehyde
Ethylene glycol
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Solution
Ethylene glycol
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\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{Cl}\phantom{..}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
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