Advertisements
Advertisements
Question
Encircle the odd one of the following.
Options
(–9) × 5 × 6 × (–3)
9 × (–5) × 6 × (–3)
(–9) × (–5) × (–6) × 3
9 × (–5) × (–6) × 3
Advertisements
Solution
(–9) × (–5) × (–6) × 3
Explanation:
- (–9) × 5 × 6 × (–3) = –810
- 9 × (–5) × 6 × (–3) = 810
- (–9) × (–5) × (–6) × 3 = –810
- 9 × (–5) × (–6) × 3 = 810
∴ (–9) × (–5) × (–6) × 3 is different.
APPEARS IN
RELATED QUESTIONS
Find the product of (−35) × 22
Find the product of (−10) × 12 × (−9)
Find the product of (−25) × 0 × 45 × 90
The product of two integers is −135. If one number is −15. Find the other integer
Find the product of (−30) × (−70) × 15
If we multiply six negative integers and six positive integers, then the resulting integer is ______.
If we multiply five positive integers and one negative integer, then the resulting integer is ______.
Difference of two negative integers cannot be a positive integer.
(–1) × (–2) × (–3) = 1 × 2 × 3
Product of three negative integers is a negative integer.
