Advertisements
Advertisements
Question
Electrode potentials (E0) are given below:
Cu+/Cu = + 0.52 V,
Fe3+/Fe2+ = + 0.77 V,
\[\ce{1/2I2(s)/I^-}\] = + 0.54 V,
Ag+/Ag = + 0.88 V
Based on the above potentials, the strongest oxidizing agent will be:
Options
Cu+
Fe3+
Ag+
I2
MCQ
Advertisements
Solution
Ag+
Explanation:
The higher the reduction potential value, the stronger the oxidizing agent; thus, based on the given values, Ag+ will be the strongest oxidizing agent.
shaalaa.com
Redox Reaction and Electrode Potential
Is there an error in this question or solution?
