Question

Electrode potentials (E⁰) are given below:

Cu⁺/Cu = + 0.52 V,

Fe³⁺/Fe²⁺ = + 0.77 V,

\[\ce{1/2I2(s)/I^-}\] = + 0.54 V,

Ag⁺/Ag = + 0.88 V

Based on the above potentials, the strongest oxidizing agent will be:

पर्याय

• Cu⁺

• Fe³⁺

• Ag⁺

• I₂

Answer 1

Ag⁺

Explanation:

The higher the reduction potential value, the stronger the oxidizing agent; thus, based on the given values, Ag⁺ will be the strongest oxidizing agent.